The Helping Me in Geometry Thread (1 Viewer)

Menomaths · Sep 8, 2013

Triangle QPS looks like an extension from triangle QSR, and the other triangle is QPR, which already includes the extension so how can they be the same

HeroicPandas · Sep 8, 2013

Menomaths said:
Triangle QPS looks like an extension from triangle QSR, and the other triangle is QPR, which already includes the extension so how can they be the same

Get triangle PQS and QSR, combine them. The resultant area will be the same as triangle PQR

Menomaths · Sep 8, 2013

HeroicPandas said:
Get triangle PQS and QSR, combine them. The resultant area will be the same as triangle PQR

Exactly, how are the two triangles the same then
When you said the two triangles are same did you mean triangle QPR and QSR are the same?

HeroicPandas · Sep 8, 2013

$\rightarrow \\ A_{PQR} = \frac{1}{2} \cdot PQ \cdot QR \\ = \frac{1}{2} \cdot 12 \cdot 16 \\\\ = 96$

$\rightarrow \\A_{QPR} = \frac{1}{2} \cdot QS \cdot PR \\ \\ ~~~~~~=\frac{1}{2}\cdot PR \cdot QS$

But $A_{PQR} = A_{QPR}$

HeroicPandas · Sep 8, 2013

Menomaths said:
Exactly, how are the two triangles the same then
When you said the two triangles are same did you mean triangle QPR and QSR are the same?

Triangle (PQR) = Triangle (QPR)

Menomaths · Sep 8, 2013

HeroicPandas said:
$\rightarrow \\ A_{PQR} = \frac{1}{2} \cdot PQ \cdot QR \\ = \frac{1}{2} \cdot 12 \cdot 16 \\\\ = 96$

$\rightarrow \\A_{QPR} = \frac{1}{2} \cdot QS \cdot PR \\ \\ ~~~~~~=\frac{1}{2}\cdot PR \cdot QS$

But $A_{PQR} = A_{QPR}$

I was comparing different triangles =.=
Now I get it thanks so much!

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The Helping Me in Geometry Thread (1 Viewer)

Menomaths

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HeroicPandas

Heroic!

Menomaths

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HeroicPandas

Heroic!

HeroicPandas

Heroic!

Menomaths

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