Tricky questions (1 Viewer)

[chousta]

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[L=Lawliet]

wo.. they are hard... do you have any tricky solutions?

 

[wrxsti]

they arent that bad....just integrate the inverse reciprocal of cosinex and invert with respect to "q" you then achieve an expression for dt/dy which is approximetaly equal to the squareoot of the rth term in the expanion of pie x cubed c .

 

[chousta]

they arent that bad....just integrate the inverse reciprocal of cosinex and invert with respect to "q" you then achieve an expression for dt/dy which is approximetaly equal to the squareoot of the rth term in the expanion of pie x cubed c .

yea the 1st part is easy mate....

nah no solutions i have written some of my own but im not sure if they r correct.