Slidey But pieces of what? Joined Jun 12, 2004 Messages 6,600 Gender Male HSC 2005 Apr 23, 2005 #21 sinx.sec^2(x)=sinx/cos^2(x) and: tanx.secx=sinx/cosx * 1/cosx=sinx/cos^2(x) Identical.
V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 23, 2005 #22 okies cool. Fitz had one way, and i dont trust myself. Is there a preferred way of writing them or...does it not matter at all? Last edited: Apr 23, 2005
okies cool. Fitz had one way, and i dont trust myself. Is there a preferred way of writing them or...does it not matter at all?
Slidey But pieces of what? Joined Jun 12, 2004 Messages 6,600 Gender Male HSC 2005 Apr 23, 2005 #23 No problem. You should grow more confident with your skills as the year progresses.
V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 24, 2005 #24 next one erghh.... Find area under 1- cos x between pi/2 and 0. Last edited: Apr 24, 2005
V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 24, 2005 #25 And one more: Given that Integral of 4/(1+x^2) dx = pi, find approximate values of pi using: (a) Trapezoidal rule with two strips thanks in advance
And one more: Given that Integral of 4/(1+x^2) dx = pi, find approximate values of pi using: (a) Trapezoidal rule with two strips thanks in advance
Slidey But pieces of what? Joined Jun 12, 2004 Messages 6,600 Gender Male HSC 2005 Apr 24, 2005 #26 Find area under 1- cos x between pi/2 and 0. Integral 1-cosx dx = x-sinx from 0 to pi/2 =pi/2 - 1 And I don't know trapezoidal rule, sorry.
Find area under 1- cos x between pi/2 and 0. Integral 1-cosx dx = x-sinx from 0 to pi/2 =pi/2 - 1 And I don't know trapezoidal rule, sorry.
V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 24, 2005 #27 Ok, i think the book is wrong. thanks.