K keropi Member Joined Mar 12, 2005 Messages 43 Gender Undisclosed HSC N/A Mar 7, 2006 #1 hey can anyone please help me in this question ..im really struggling in trig find the area of the minor segment coreect to 2 dp given radius is 5.9cm and the angle subtended is 23 degreess 12 minutes thanks
hey can anyone please help me in this question ..im really struggling in trig find the area of the minor segment coreect to 2 dp given radius is 5.9cm and the angle subtended is 23 degreess 12 minutes thanks
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Mar 7, 2006 #2 Convert 23o 12' to radians by multiplying it by pi/180. Area= 1/2 x r2 [theta - sin(theta)] (make sure theta is in radians) and substitute your values in.
Convert 23o 12' to radians by multiplying it by pi/180. Area= 1/2 x r2 [theta - sin(theta)] (make sure theta is in radians) and substitute your values in.
K keropi Member Joined Mar 12, 2005 Messages 43 Gender Undisclosed HSC N/A Mar 7, 2006 #3 hey riviet thanks for your help!
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Mar 7, 2006 #4 It was my pleasure, glad to help.
