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Trig proving (1 Viewer)

crex

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Hey guys,
how do you prove this?

Thanks!
 
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Solution

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A little rusty eheh but...

Sin2x = 2SinxCosx

So if you consider:

Sin2[(a-b)/2] = 2Sin[(a-b)/2]Cos[(a-b)/2]

Therfore:

Sin(a-b) = (as above)
 

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