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Trig (1 Viewer)
- Thread starter skillz
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darkliight
I ponder, weak and weary
You mean (0,pi] right?
Maple tells me there is two solutions on that interval and I think Newton's method with f(x) = sin^2(theta) - theta/pi should converge (slowly) to either of those numbers .... starting at 2pi/19 will get one of them, correct to two decimal places, quickly though.
Maple tells me there is two solutions on that interval and I think Newton's method with f(x) = sin^2(theta) - theta/pi should converge (slowly) to either of those numbers .... starting at 2pi/19 will get one of them, correct to two decimal places, quickly though.
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