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skillz

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Solve correct to two decimal places, the equation sin^2theta = theta/pi for theta [0,pi]
 

darkliight

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You mean (0,pi] right?

Maple tells me there is two solutions on that interval and I think Newton's method with f(x) = sin^2(theta) - theta/pi should converge (slowly) to either of those numbers .... starting at 2pi/19 will get one of them, correct to two decimal places, quickly though.
 
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