Trignometry? (1 Viewer)

[Zokunu]

Littlehelp?

Solve for -180≤θ≤180, round you answers to the nearest degree?

√3 tan3θ + 1 = 0

THX

 

[Parvee]

 

[Zokunu]

thx man but was that meant to say -540≤θ≤540?

Bumping this since i need help with another question related to: Tangents and Normals

If the slopes of the tangents to the curve y= ax^2 + bx + c are 4 and -14 at the points (1,5) and (-2,20) respectively, find a, b and c.

Thanks

 

[kev-kun]

Dunno if I'm right but it should be this, excuse my crappy handwriting =='

 

[Zokunu]

Dunno if I'm right but it should be this, excuse my crappy handwriting ==' View attachment 28562

ye I checked, that's right man thx appreciate it . I have my yearlies coming up so i might ask a lot of questions...

The gradient of the normal to the curve y= a/x + b at the point (3,-5) is 3. Calculate the values of a and b.

I was wondering if this is how you do it...:

y=a/-3 + b = -5

Differentiate y=a/x+b?
ax^-1?

I think i did it wrong...littlehelp?

 

[funnytomato]

ye I checked, that's right man thx appreciate it . I have my yearlies coming up so i might ask a lot of questions...

The gradient of the normal to the curve y= a/x + b at the point (3,-5) is 3. Calculate the values of a and b.

I was wondering if this is how you do it...:

y=a/-3 + b = -5

Differentiate y=a/x+b?
ax^-1?

I think i did it wrong...littlehelp?

that's right
just use d/dx x^n = n x^(n-1) , with n=-1( which you've already shown)

 

[levaly]

Here is a step by step solution:

http://www.symbolab.com/solutions/t...t{3}\tan\left(3θ\right)+1=0, -\pi\le θ\le \pi