excuse me, i know that x+2/x-1 is the same as 1 +3/(x-1)why dont you do y=1 +3/(x-1)....and it should have an asymptote at x=1 and as x approaches infinity y should approach 1
One approach is long division, which is in Extension 1 polynomials.excuse me, i know that x+2/x-1 is the same as 1 +3/(x-1)
how did u actually get to that?
I think this guy is losing it. He's talking to himself.apparently it is, thats why i deleted my post.
Ha, lol, and the long division crap? i laugh at you allexcuse me, i know that x+2/x-1 is the same as 1 +3/(x-1)
how did u actually get to that?
everyone please remember to use brackets, what you have just written is this:y=x+2/x-1
what is the domain and range
That's a very minor point.everyone please remember to use brackets, what you have just written is this:
If you meant to write that then that's ok, but if you meant to write this: then you need to write it like this: (x+2)/(x-1)
everyone please remember to use brackets, what you have just written is this:
If you meant to write that then that's ok, but if you meant to write this: then you need to write it like this: (x+2)/(x-1)
Yeah but we know what the OP means... although yes, you should technically do it.He does have a valid point you know.
If you really want to be that pedantic; you didn't quantify what 'k' is. ie, is 'k' a function of x, or a constant, or...?Help!
Differentiate e^k/x
I stand by frenzal's point.
Where k is a constant.If you really want to be that pedantic; you didn't quantify what 'k' is. ie, is 'k' a function of x, or a constant, or...?
You obviously did get my point. My point was that you were being a pot calling the kettle black. If you were so perfect and so on, then you would've defined everything in your post, but you didn't so it shows something about youWhere k is a constant.
So yea, hows that?
Even if you did get k is a constant, I doubt you'll get correct answer without posting both solutions.