vector question (1 Viewer)

[user18181818]

please in desperate need of help

 

[SB257426]

a) (a-p).(b-p) = PA.PB and we know angle APB is a right angle so PA and PB are 0 and so their dot product will be 0

 

[SB257426]

 

[SB257426]

here u go
this and previous pic is b)

 

[SB257426]

also can u check if this is correct or not?

 

[SB257426]

part iii )




ok so the equation in the second line is saying the distance from M to P is the same as the distance from B to M. So if u draw a triangle with this information u can deduce that PM bisects right angle and angle MPA = angle MPB = 45

look im not really sure what piece of info they want exactly about p but this is all i know

 

[user18181818]

View attachment 40170

how did u get from 3rd line to 4th? like i get that u subbed in m=1/2(a+b) but how did u change the magnitude of p to p dot product with a+b

 

[user18181818]

this is the answer btw for ii

 

[SB257426]

how did u get from 3rd line to 4th? like i get that u subbed in m=1/2(a+b) but how did u change the magnitude of p to p dot product with a+b

I used part i to rearrange for p.p (expand it)

 

[SB257426]

View attachment 40174View attachment 40175
this is the answer btw for ii

Ok so I did get it correct but didnt continue .. my bad

 

[Luukas.2]

For the last part, it proves that the midpoint of the hypoteneuse of a right-angled triangle is equidistant from all three vertices.

 

[SB257426]

View attachment 40171

here u go
this and previous pic is b)

@carrotsss whats with the laughing emoji lol, is it cuz i used desmos lol