Finx
Member
- Joined
- Mar 29, 2008
- Messages
- 375
- Gender
- Male
- HSC
- 2009
Find the volume of the solid formed when the curve y=(x+5)² is rotated about the y-axis from y=1 to y=4.
So far I've got;
V = pi∫x²dy
y = (x+5)²
y = x² + 10x + 25
x² = y - 10x - 25
I'm stuck here - what do I do with the single x term?
Thanks in advance
So far I've got;
V = pi∫x²dy
y = (x+5)²
y = x² + 10x + 25
x² = y - 10x - 25
I'm stuck here - what do I do with the single x term?
Thanks in advance