Weak/Strong acids - am frustrated! (1 Viewer)

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OK, this is what my textbook says about weak acids:

~*~

Most acids are only partially ionised in water and are therefore classified as weak acids. The ionisation of the weak acid, ethanoic acid, can be represented by the following equations:

CH3COOH (aq) <--> H+(aq) + CH3COO- (aq)

or

CH3COOH (aq) + H2O (l) <--> H3O+ (aq) + CH3COO- (aq)


The reversible arrows indicate that an equilibrium is established between ethanoic acid molecules and hydrogen ions and ethanoate ions. In terms of the Bronsted-Lowry theory CH3COOH is a weaker acid (proton donor) than H3O+, and H2O is a weaker base (proton acceptor) than CH3COO-. The reverse reaction is therefore favoured, so that at equilibrium only a small proportion of ethanoic acid molecules are ionised.

~*~

I don't get the bolded part. Could someone PLEASE explain this to me? Am feeling quite desperate.:worried:
 

Nodice

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Consider it like this: The conjugate base of a weak acid is a strong base. The conjugate of a weak base it a strong acid.
The acetic acid is the weak acid, and so CH3COO- will be a strong base. H2O is a comparatively weak base, and so its conjugate, H3O+ will be a strong acid. Since the products are stronger acids/bases, they will want to react more and so the equilibrium is to the left.
 
P

pLuvia

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Acids and bases have conjugates to itself

Eg

CH3COOH the conjugate base is CH3COO-
CH3COO- the conjugate acid is CH3COOH

CH3COOH (aq) + H2O (l) <--> H3O+ (aq) + CH3COO- (aq)

Here acetic acid being a proton donor donated a H+ to H2O hence why it has a negative charge on it
 

Nodice

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The product ions react very easily to reform the acid and the water. They want to react more than the acetic acid and water.
Maybe an analogy will work? - Sodium is a more reactive metal than gold, and so it will react much easier with water than gold ~ consider sodium like the strong products, and gold as the weak reactants.
 

Riviet

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Weak acids will only ionise partially, meaning that some of the acid will remain unreacted while the rest react with the water to form acetate ions and hydronium.
 

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