Using that identity, it becomes S 1/2 (1 - cos4x) = ....MarsBarz said:Thanks.
What about this integration(I):
I (sin 2x)^2 dx
It was in my trial today and I didn't know how to do it because of the 2x. Had it been x I could have simply substituted the trig identity (sinA)^2=1/2(1-cos2A) but what should I have done in this particular case?