basically yes. just mention the colour changes as u increase the temp.. (from red to purple), and changes to red again when u cool it down again.
mention how u heat it (using bunsen), draw diagram if the number of marks sounds appropriate
u analyse the equil qualitatively just by observing the colour change
dont forget to mention the eqn.
just for other ppl to know, the equil is
[Co(H2O)6]2+ (aq) + 2Cl- (aq) <--> Co(H2O)4Cl2 (aq) + 2H2O (l)
[Co(H2O)6]2+ is maroon
Co(H2O)4Cl2 is dark blue
note: it's Co not CO (carbon and oxygen)
Co(H2O)4Cl2 is basically CoCl2 when its dissolved in water, i.e. in aqueous form.
the conc which can be played around with is
-> the water conc (add more water; add ethanol to decrease water becoz it binds the water molecules and decrease the amount of free water molecules.. u dont heat it to evaporate becoz it changes temp)
-> the Cl- ion conc.. u can add HCl to increase.. add more water to decrease its conc