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what is integral coefficient? (1 Viewer)

totallybord

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hi
i was just wondering if soemone could tell me what integral coefficient is in a polynomial?
thank you
 

totallybord

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hi
umm how wld u graph a polynomial with an exponent of 4 like (x-1)^4 ?
thanks
 

totallybord

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umm i havent learnt calculus yet... can soemone do a graph of what (x-1)^4 woudl look like?
thanx a lot :D
 

Riviet

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The curve is shaped like a very steep parabola with vertex (1,0) and y-intercept 1.
 
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totallybord

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so there's nothing specially shaped for a ^4 ? its just a parabola?
 

airie

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If it's just a single term kx4+c (where k and c are constants) then yes, just a parabola, except it's flatter in the interval [-1, 1] and steeper when x<-1 and x>1. But it can also make an M or W shape (depends on the sign of k) when the polynomial is, say, x4-x2+4, where there are more than just one x term.
 

Raginsheep

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Its not a parabola. A parabola is a specific locus which x4 does not obey. It is shaped in a similar manner to a parabola though.
 

totallybord

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i heard that you can write it as ((x-1)^2)^2 so its a parabola squared?? so i still dun get how u draw that ....
 

Raginsheep

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It may be a parabola squared. But airie said it was a parabola which I pointed out was wrong. Just because x2 is x squared, doesn't still make it a linear line.
 

airie

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Raginsheep said:
It is shaped in a similar manner to a parabola though.
Yeah, that's what I meant :eek: Not very specific diction there :p

LottoX said:
All even powers look like parabolas, (the higher the power, the more it looks like a beaker).
But some would have 'bumps' for x values near its axis of symmetry, making a W or M shape - like the x4-x2+4 mentioned above :p
 

totallybord

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ummm is (x^2 -1)... wld u graph it as a parabola?
im a bit confusedd
thanks for ur help :d
 

airie

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SoulSearcher said:
Isn't the normal parabola graph shifted 1 unit down for that graph?
Yeah I think that's what he meant. :p (x-1)2 would be the standard parabola shifted 1 unit to the right.
 

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