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What's wrong with my working? (complex no.'s q.) (1 Viewer)

hasm

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Joined
May 6, 2003
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11
(Question 3 (a) from the CSSA trial)
question was something like find values of x if x is real and (x + i)^4 is imaginary.

here's what I did:
= x^4 + 4x^3i + 6x^2i^2 + 4xi^3 + i^4
= x^4 - 6x^2 + 1 + i(4x^3 - 4x) -> imaginary, real part = 0

ie x^4 - 6x^2 + 1 = 0
using the quadtratic formula,
x^2 = (6 +/- sqrt(32)) / 2

x^2 = 3 +/- 2sqrt(2)

x = +/- sqrt(3 +/- 2sqrt(2))
(I then wrote out the 4 answers.)

teacher's response, on the exam, was: "this should work & I can't find your mistake!"
I can't see the mistake either... :(
 

Richard Lee

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Sep 12, 2003
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The final solutions:
x=(+/-)[sqrt(2) +/- 1] since x^2=3 +/- 2sqrt(2)=(sqrt(2) +/- 1)^2
If u don't understand. Call me. 0413 197 399
 

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