When chemical bonds are formed they release energy and when they are broken they require energy. Comparatively, it takes less energy to break the bonds in an alkanol (C-H, C=O, C-O) and in oxygen (O=O) during combustion than is released by bonds forming in CO
2 (C=O) and H
2O (O-H) (products of combustion), so the enthalpy change is negative. In longer chain alkanols, you have more CO
2 and H
2O forming, which releases more energy than it takes to break the extra bonds in the alkanol and oxygen.
I'm pretty sure that's right, but it's outside the syllabus - you only need to identify why longer chained alkanols have higher melting and boiling points, off the top of my head.
I_F