Worked Solutions (1 Viewer)

[goan_crazy]

Attn: Slide Rule, Acmilan, Xayma or anyone that wants to, can you please post up worked solutions to the 2005 Maths HSC paper
I think Ralph is gonna post it up, so once its done could we please get the solutions like how the CSSA trial was done
Cheers!

 

[r.haidar]

yep the test is up now, i can work thru it and post the solutions but it will be a while... coz i got 3 unit on thurs... so its upto u mods!

peace out
ralph

 

[Xayma]

Well lets see,

a) You posted it where it is unlikely we would go, I just stumbled here by chance.
b) Slide Rule has Maths Ext 1 on thursday
c) Acmilan has at least one assignment due friday
d) I have 5 due friday.

I could do them on saturday, but that might be unlikely.

 

[Slidey]

Joe, feel free to write up solutions yourself, now that you are no longer constrained by the time restrictions of the exam. I'd be happy to sticky them in the maths forum.

 

[KeypadSDM]

Gee, thanks alot for asking I've got plenty of time ... until Uni exams.

ARGH!

 

[Jago]

yeah joe, write up your solutions and they can correct you.

 

[Meads]

I will do question 1, even then there will be mistakes. lol.

 

[goan_crazy]

I'll do the solutions for question 1 and maybe 2
I'll see how it goes
That will be a good start to it

I'm not confident with my results for the rest except a few parts of questions, anyway I'll do what I can and then if I'm wrong I can be corrected I guess...
Anyone can assist in the others would be great

 

[acmilan]

"c) Acmilan has at least one assignment due friday"

Electrical engineering exam wednesday
IT major due thursday
Computer science exam friday

However im off tomorrow so if someone hasnt dont it already i might give it a go.

 

[icycloud]

I'll type up some solutions =D

Q1

(a) 3.7 (2sf)

(b) x³-27 = (x-3)(x²+3x+9)

(c) ∫4+sec²x dx = 4x + tan(x) + C

(d) (2x-3)/2 - (x-1)/5 = [5(2x-3)-2(x-1)]/10
= [10x-15-2x+2]/10
= (8x-13)/10

(e) |x-3| <= 1
(x-3)² <= 1
x²-6x+9-1 <= 0
x²-6x+8 <=0
(x-2)(x-4) <= 0
{2 <= x <= 4}

(f) x² = 8(y-1)
4a = 8, a = 2
Vertex (0,1), parabola is of the form x² = 4ay (concave up)
Thus, Focus = (0, 1 + a) = (0, 3)

 

[Pianpupodoel]

I had plenty of time this afternoon so I cooked up a document with the answers only. Proofs are not there, nor are worked solutions.

Feel free to add proofs and what not, this effort was just to see how many silly calculation errors I made.

Hopefully all are correct =D

 

[goan_crazy]

answers only atm
this is what I got
Question 1
a) 3.7
b) (x+3)(x^2 + 3x +9)
c) 4x + tanx + C
d) 8x-13 / 10
e) x less than or equal to 4, x greater than or equal to 2
f) I got (1,2) this is definitely wrong. Whoever knows the right answer post it up

Question 2:
a) pi/4, 7pi/4 (sorry couldn't get the pi symbol on the comp)
b) (i) –cox x^2 + sin x
ii) x^2 – 2x / (x-1) ^ 2
c) (ii) ½ ln (x^3 + 1) + C
ii) ½
d) y – x +1 – e

Please correct me on the one's I got wrong
Anyone who wants to do the rest of the paper, feel free

 

[Kutay]

answers only atm
this is what I got
Question 1
a) 3.7
b) (x+3)(x^2 + 3x +9)
c) 4x + tanx + C
d) 8x-13 / 10
e) x less than or equal to 4, x greater than or equal to 2
f) I got (1,2) this is definitely wrong. Whoever knows the right answer post it up

Question 2:
a) pi/4, 7pi/4 (sorry couldn't get the pi symbol on the comp)
b) (i) –cox x^2 + sin x
ii) x^2 – 2x / (x-1) ^ 2
c) (ii) ½ ln (x^3 + 1) + C
ii) ½
d) y – x +1 – e

Please correct me on the one's I got wrong
Anyone who wants to do the rest of the paper, feel free

Your answer to Question 1 part b is wrong it was like (x-3)(x^2 + 3x +9)
I AM PISSED I MISSED QUESTION 2 part E 2marks down the drain and easy marks as well

 

[Kutay]

Hey for question 8 part c part iii
I was wondering if i will get this answer correct!!! as i have been relooking over it and it says in WHICH YEAR but i just say n-12.444 n = 13 And this said that In the 13th YEAR it will be paid off!!! Technically i think that is still correct!!! like cause i say in the 13th YEAR, was are ur opinions ?

 

[rnitya_25]

sorry kutay, but it is wrong. im only saying it from doing a psat paper on that type of qestion, and you have to add it to 2005 and say what year it was. i think it was during the year 2017 if i remember correct.
i kinda wanna forget about this paper and the crappyness of the paper in certain parts which is why i don't wanna post up my answers.

 

[LostAuzzie]

I had plenty of time this afternoon so I cooked up a document with the answers only. Proofs are not there, nor are worked solutions.

Feel free to add proofs and what not, this effort was just to see how many silly calculation errors I made.

Hopefully all are correct =D

Well by your answers (and my memory of what I put) I'd get around raw mark 110.
They look right to me.

 

[MCOLT]

the probabilty question is wrong the one where it goes what is the chance that each colour has a winning ticket cos you have to take in different arangements there are 6 of em

rgb rbg
brg bgr
gbr grb

is about 95/96 what you need for a band 6 me hopes

 

[seremify007]

Damn I got that focus Q wrong... i got a=2, but forgot that the vertex wasn't at 0,0 >_>

 

[shiroangel]

for Q7 a)i) isnt the answer ($2500 x 13) + 50000 = $82500
and ii) 50000(1.04)^13 = $83253.65

are these rite??

 

[snickerdoodle]

for Q7 a)i) isnt the answer ($2500 x 13) + 50000 = $82500

Ahh, you forgot the -1. Formula for T13=a+(n-1).d

So it's ($2500x12)+$50000=$80000

I got the same answer for part ii .