Australian Maths Competition (1 Viewer)

[Official]

Re: Australian Mathematics Competition

how do you actually do that question?
= =MAN i feel inferior to you guys lol.

I wrote how I did it earlier in this post somewhere.

 

[Hypermelon]

Re: Australian Mathematics Competition

I got 60.

q14?
yeah i think it was 60. but i put 48 down

in x^2+y^2=50, 50 is the radius squared, so the radius would be a little bigger than 7
anyway, for the x-axis 0-7 would be included. also -7 to -1. So there are 15 possible integer values for x, and 15 integer values for y. for each value there are 2 values, a +ve and -ve so 30*2=60

grr

 

[Official]

Re: Australian Mathematics Competition

q14?
yeah i think it was 60. but i put 48 down

in x^2+y^2=50, 50 is the radius squared, so the radius would be a little bigger than 7
anyway, for the x-axis 0-7 would be included. also -7 to -1. So there are 15 possible integer values for x, and 15 integer values for y. for each value there are 2 values, a +ve and -ve so 30*2=60

grr

Yah, thats how I did it, was one of the harder questions from 11-20

 

[Aquawhite]

Re: Australian Mathematics Competition

I had to really think about that above one... clearly I had the wrong mindset XD.... I didn't put down 60...

 

[Iruka]

Re: Australian Mathematics Competition

q14?
yeah i think it was 60. but i put 48 down

in x^2+y^2=50, 50 is the radius squared, so the radius would be a little bigger than 7
anyway, for the x-axis 0-7 would be included. also -7 to -1. So there are 15 possible integer values for x, and 15 integer values for y. for each value there are 2 values, a +ve and -ve so 30*2=60

grr

You have to make sure that you don't count points such as (1,7) and (5,5) which have both an integral x and y coordinate twice. That is why 48 is the correct answer.

 

[Aquawhite]

Re: Australian Mathematics Competition

You have to make sure that you don't count points such as (1,7) and (5,5) which have both an integral x and y coordinate twice. That is why 48 is the correct answer.

I'm hoping I put 48 down... I'm not exactly sure what I did put :S...

 

[Hypermelon]

Re: Australian Mathematics Competition

You have to make sure that you don't count points such as (1,7) and (5,5) which have both an integral x and y coordinate twice. That is why 48 is the correct answer.

lol o yea then i hope i get points for that one

 

[IndianPrideBby]

Just flicking through my diary seeing the date that term 3 starts, i stumble upon the heading Australian Maths Competition. Apparently on my dairy it says it is on the August 6th (Thursday). Has any body done this from past years? Was it hard? easy? Also any past papers if possible? Thank you in advanced for reply. btw im in year 10 (2009).

lolsz
ive dun da math comp yr 7, 9, n this yr...yes it was hard! buh it was neva as hard as this yrs intermediate paper...last yr i got a credit>>>cos it wasnt thaaat hard<<<THIS class=inlineimg title="" smilieid="20" alt="" border="0" src="http://community.boredofstudies.org/images/smilies/uhoh.gif" participation..<img a get ila bet yr...i />.


u cant realli study 4 it - trust meh, i tried, 3 yrs experience bro

past papers - i think u can get past papers...i checkd tha last page n it said u can order it...jus check out tha Australian Maths Trust website...u can get papers that mite help frm books in angus n robs or sum bookstore...





nywaiiz...i dint get that or any quetions frm Q 11 - 30

 

[Official]

Re: Australian Mathematics Competition

You have to make sure that you don't count points such as (1,7) and (5,5) which have both an integral x and y coordinate twice. That is why 48 is the correct answer.

Oh shit

 

[Dragonmaster262]

Re: Australian Mathematics Competition

The AMC is generally a problem solving exam. You will see that the first 10 questions are rudimentary. The next 5 will be more problem solving, the last 15 will be problem solving although knowledge of both number theory and combinatorics and a solid understanding of geometry and algebra would certainly make the last few questions 5 times easier.

Do you reckon that's all you need to get a High Distinction?

The first time I did it I got a Proficiency, whatever that is.

 

[Official]

Re: Australian Mathematics Competition

Do you reckon that's all you need to get a High Distinction?

The first time I did it I got a Proficiency, whatever that is.

You'll need to know much more than that for a HD but what Kurt said is true in essentials. General aptitude of maths is also what is of essence to score highly in this sort of competitions.

 

[Iruka]

Re: Australian Mathematics Competition

To do well at these sort of competitions, I think you need to know a bit more Euclidean geometry than is in the syllabus and some basic number theory. Plus the ability to think laterally.

All these things can be developed with practice, but you probably aren't going to pick them up just in your standard maths classroom.

 

[Aquawhite]

Re: Australian Mathematics Competition

The competitions are only for mathy-geeky fun ^_^

Don't worry if you go bad or go terrible infact.... You've only lost $4.50 and if you're smart you earned a free question booklet to confuse all your non-mathematically minded friends XD...

I just think they're interesting to enter into - regardless my result.

 

[IndianPrideBby]

Re: Australian Mathematics Competition

The competitions are only for mathy-geeky fun ^_^

Don't worry if you go bad or go terrible infact.... You've only lost $4.50 and if you're smart you earned a free question booklet to confuse all your non-mathematically minded friends XD...

I just think they're interesting to enter into - regardless my result.

@ our skewl...yr 10 dint hav 2...its compulsory 4 all of yr 10
s0o i got my money bak

 

[mastermind666]

Re: Australian Mathematics Competition

i did the intermediate paper today - felt quite good about it lol

i reckon:

1-10 =30 marks
11-20 = 40 marks
21-25 = 20 marks (stuffed one question, careless mistake)
26, 27, 28, 29 solved = 30 marks

Total = 120 marks

for 26-29, were the answers 419, 578, 31, 231?

 

[pwoh]

Re: Australian Mathematics Competition

I don't think this counts for a valid solution...But for the ascending question, I just divided the 4 digit number given by 6...and it worked...6 marks in 1 minute.

Personally, I don't care about the mark...I only take the test to steal the question booklet afterward =]

Wasted so many minutes on that question *facepalm*

 

[Winn]

Re: Australian Mathematics Competition

Also for Q15 the eyebrow number one, what did you all get? I got A...it was a 50% guess.
and for the traitor question, what is the answer? I was pretty sure i knew the right answer before I started checking it and went around in circles!

 

[Kajixtatsu]

Re: Australian Mathematics Competition

You have to make sure that you don't count points such as (1,7) and (5,5) which have both an integral x and y coordinate twice. That is why 48 is the correct answer.

Are you sure? The question says "at least" one of the x, y. Not only one of the coordinates x, y. Nor at most 1...

 

[lolokay]

Re: Australian Mathematics Competition

he means don't count (1,7)etc. for both "x is an integer", and "y is an integer", as you'll count it twice

 

[Kajixtatsu]

Re: Australian Mathematics Competition

Oh, I read too fast and missed twice, my bad