vectors - the triangle inequality (1 Viewer)

[ninetypercent]

alright, I can prove it but can someone explain to me why this can only hold when argz1 = zrgz2 = @.

Thanks

 

[GUSSSSSSSSSSSSS]

when argz1 = argz2 = @ the shape is a straight line

the hypotenuse and two sides are all contained on the one line, the length of the line is determined by the hypotenuse, but also since the other 2 sides must connect at the corners the 2 sides also cover the distance of the hypotenuse

thus the sum of the sides = the hypotenuse


....ima sorry for the really shit explanation but i hope it paints a sort of picture that you can understand =S

 

[ninetypercent]

alright thanks

repped

 

[biopia]

alright, I can prove it but can someone explain to me why this can only hold when argz1 = zrgz2 = @.

Thanks

Is that meant to be argz1 = zargz2 = @ ?

If so, I think that is just saying the two arguments cannot be the same, hence why the second argument is multiplied by some other complex number z (because when you multiply complex numbers, the argument changes e.g. multiplying by i is a rotation of z through 90 degrees) Pretty sure you'd already know that, but I can't assume Early days yet.

As the previous poster said, if the arguments are the same, then the triangle is just a straight line, hence why the inequality triangle relationships only hold when the arguments are different =]

Hope that helps!