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Quick Complex (1 Viewer)

Thread starter nrlwinner
Start date Dec 19, 2009

N

nrlwinner

Member

#1

How does mod (2 - iz) change to mod (z + 2i)

addikaye03

The A-Team

#2

nrlwinner said:
How does mod (2 - iz) change to mod (z + 2i)

Let z=k|2-iz| where k is a factor

|i||2-iz|=|2i-i^2z|

=|z+2i|

So it's a factor of i

Do you see?

N

nrlwinner

Member

#3

Yes I do. Thanks very much.

N

nrlwinner

Member

#4

Got another one here.

How do you change

mod (1+i/z - 2) = 2 to mod (z - 1+i/2) = mod (z)

N

nrlwinner

Member

#5

Anyone?

untouchablecuz

Active Member

#6

$\\|\frac{1+i}{z}-2|=2\\|\\|\frac{1+i-2z}{z}|=2\\\frac{|1+i-2z|}{|z|}=2\\\frac{|1+i-2z|}{2}=|z|\\\frac{|1+i-2z|}{|2|}=|z|\\|\frac{1+i-2z}{2}|=|z|\\|\frac{1+i}{2}-z|=|z|\\|-(z-\frac{1+i}{2})|=|z|\\|z-\frac{1+i}{2}|=|z|$

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