a quick question (1 Viewer)

[mc1007]

Find in index notation


I know this is a simple case of substitution but i'm not sure how this can be expressed in index notation. Any help appreciated.

 

[4025808]

First of all substitute a, b and c in

and then i'll show you below

(2^4/5^4)/(-1^3/3^3)x(3^4/5^4)

you can eliminate 5^4 from top and bottom as the cancel out
you then also eliminate 3^3 and the 3^4 becomes 3^1

multiply the rest of them together and you get 2^4/-3
and then it becomes 2^4 x -3^-1

since (1/-3) = -3^-1

the answer would be -16/3 but because you have to express it in index notation therefore its 2^4 x -3^-1

 

[Amogh]

http://latex.codecogs.com/gif.latex?\left%20(%20\frac{2}{5}%20\right%20)^4%20\left%20(%20\frac{-3}{1}%20\right%20)^3%20\left%20(%20\frac{5}{3}%20\right%20)^4%20=%20\frac%20{2^4%20\times%20-1}{3}%20=%20\frac%20{-16}{3}

 

[mc1007]

Thanks so much!!

 

[pman]

this should be in the maths forum

 

[mc1007]

this should be in the maths forum

it is.

 

[t00l]

it is.

nope

 

[hscishard]

nope

Yup it is

 

[iRuler]

it's in the prelim forum m8

 

[ohexploitable]

OP posted that same question in the Maths section.

 

[pman]

this is most def general discussion