L Lindurr Premium Member Joined Jan 14, 2010 Messages 27 Gender Undisclosed HSC 2011 Apr 10, 2012 #1 find the y value of the point whose value is 7 if the point lies on the curve y=f(x) defined by f'(x) = f(x) Thanks
find the y value of the point whose value is 7 if the point lies on the curve y=f(x) defined by f'(x) = f(x) Thanks
deswa1 Well-Known Member Joined Jul 12, 2011 Messages 2,256 Gender Male HSC 2012 Apr 10, 2012 #2 Consider the curve f(x) being the line y=0. Therefore f'(x)=0 and f(x)=0 so this satisfies the conditions. When x=7, y=0, therefore the y value is 0.
Consider the curve f(x) being the line y=0. Therefore f'(x)=0 and f(x)=0 so this satisfies the conditions. When x=7, y=0, therefore the y value is 0.
Carrotsticks Retired Joined Jun 29, 2009 Messages 9,494 Gender Undisclosed HSC N/A Apr 10, 2012 #3 deswa1 said: Consider the curve f(x) being the line y=0. Therefore f'(x)=0 and f(x)=0 so this satisfies the conditions. When x=7, y=0, therefore the y value is 0. Click to expand... But this is assuming that the line y=0 is the only such curve/line satisfying the Differential Equation f'(x) = f(x). Let y = f(x) and dy/dx = f'(x):
deswa1 said: Consider the curve f(x) being the line y=0. Therefore f'(x)=0 and f(x)=0 so this satisfies the conditions. When x=7, y=0, therefore the y value is 0. Click to expand... But this is assuming that the line y=0 is the only such curve/line satisfying the Differential Equation f'(x) = f(x). Let y = f(x) and dy/dx = f'(x):
deswa1 Well-Known Member Joined Jul 12, 2011 Messages 2,256 Gender Male HSC 2012 Apr 10, 2012 #4 Carrotsticks said: But this is assuming that the line y=0 is the only such curve/line satisfying the Differential Equation f'(x) = f(x). Let y = f(x) and dy/dx = f'(x): Click to expand... Didn't think of this. Ignore my original solution.
Carrotsticks said: But this is assuming that the line y=0 is the only such curve/line satisfying the Differential Equation f'(x) = f(x). Let y = f(x) and dy/dx = f'(x): Click to expand... Didn't think of this. Ignore my original solution.