Interesting Math Problem.... (2 Viewers)

deswa1

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I've seen this before, I won't spoil it for others though :)
 

deswa1

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Im guessing it's equal to 0 also?
Yep. Look it up, its called Euler's identity. Its really interesting because it establishes a relationship between exponential functions and trigonometric functions.
 

deswa1

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I was referring to the RHS. Strictly its not part of the syllabus but its an extension of complex numbers. Essentially <img src="http://latex.codecogs.com/gif.latex?e^{ix}=cosx+isinx" title="e^{ix}=cosx+isinx" />
 

AAEldar

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I was referring to the RHS. Strictly its not part of the syllabus but its an extension of complex numbers. Essentially <img src="http://latex.codecogs.com/gif.latex?e^{ix}=cosx+isinx" title="e^{ix}=cosx+isinx" />
The derivation of it is not in the syllabus, however using e instead of cis is certainly a much better representation.
 

deswa1

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0 as x overpowers lnx. Do you want a proof for that?
 

D94

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I was referring to the RHS. Strictly its not part of the syllabus but its an extension of complex numbers. Essentially <img src="http://latex.codecogs.com/gif.latex?e^{ix}=cosx+isinx" title="e^{ix}=cosx+isinx" />
No it isn't; it's not extending on anything - it's a universal relationship or identity that we use to simplify cos(x) + isin(x) in writing, ie. a shorthand, but there is a derivation and reasoning. Strictly, the use of 'cis' or rcis(theta) is not in the NSW HSC syllabus too.
 

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or something like that

yes? yes? yes?
Not quite.

This means we are taking the product from some integer a up to some integer z such that a <= z.

It does not necessarily mean that b = a+1, c=b+1 , ... , z = y + 1.
 

Shadowdude

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Not quite.

This means we are taking the product from some integer a up to some integer z such that a <= z.

It does not necessarily mean that b = a+1, c=b+1 , ... , z = y + 1.
m8

come on, you know what i meant

why do that
 

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