qwerty44
Member
- Joined
- Oct 12, 2011
- Messages
- 557
- Gender
- Male
- HSC
- 2013
Find the gradient of the line x-2y=9.Alright, another problem.
I need to find the equation of a straight line passing through (0, -2) and perpendicular to the line x - 2y = 9. What I have tried to do so far is get the gradient of the line which is 1/2 and from there, I'm not sure what to do.
Help please![]()
Now because it has to be perpendicular, the negative reciprocal of that will be the gradient you use for the straight line. i.e You found the gradient to be 1/2, but to be perpendicular, you take the negative reciprocal which is -2. That's the gradient for the new line.
Then just use y-y1=m(x-x1) with m=-2 and the points given.