Leffife
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Using the transformation method to solve:
√2 sin(x) + cos(x) = √3
asin(x) + bcos(x) is expressed in the form Asin(x + α)
For here, what is the value of A?
Since, A = √(a² + b²) => but I'm not sure if a = √2 since if I do it, it won't be a integer.
√2 sin(x) + cos(x) = √3
asin(x) + bcos(x) is expressed in the form Asin(x + α)
For here, what is the value of A?
Since, A = √(a² + b²) => but I'm not sure if a = √2 since if I do it, it won't be a integer.