lol that triangle question can be done just using pythagoras, ymcaec just did it the way that looked complicated by using the cosine rule.whats the point of posting up such difficult questions? everyone just searches the 'hardest question' they can find in hope to challenge someone with it. I mean comeon...we are doing 4unit math questions ffs TT.TT
Here's another question. Solve for x and y:
For your equation number 4, shouldn't it be 741-x^2y^2 instead?
heres one for ya, show that the some of the numbers 1+2+3...+99+100 = 5050Any more delicious maths questions?
correcty^2 = 1/ [x(1-x)]
It is.try my q, and are you sure thats 9&10:S
b) i) 2x+y=36 (width of material)another question (procrastinating from school maths hw lol)
yestry my q, and are you sure thats 9&10:S
Correctb) i) 2x+y=36 (width of material)
Therefore y=36-2x (rearrange the equation)
ii) Area= length x height
= x x y
Sub Equation from B)i)
= x(36-2x)
= 36x x 2x^2
iii) Axis of symmetry= -b/2a
= -36/2(-2)
= -36/-4
= 9
This is the maximum value of x as it is the axis of symmetry for a parabola
iv) A=36x x 2x^2
= 36(9) -2(9)^2
= 329-162
= 167 cm2
The q looks like part of a hsc paper to me...It is.
no, it's actually cut and pasted from a past year 10 yearly examThe q looks like part of a hsc paper to me...
Oh alrighty post up another questionno, it's actually cut and pasted from a past year 10 yearly exam
there's plenty more where that came from
(just PM me)
Oops, darned windows calc -_-yes
It might seem very HSC-like with the maximum/minimum stuff, but it's really just a simple application of quadratics in year 10
Correct
however there's a calculation error in the last few steps,