HSC 2012 MX1 Marathon #2 (archive) (2 Viewers)

Sy123

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Re: HSC 2012 Marathon :)

Just going to check my step 1 here to see if I actually understand the question, Ill do the rest tomorrow too tired right now lol





Correct or way off?
 

seanieg89

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Re: HSC 2012 Marathon :)

Just going to check my step 1 here to see if I actually understand the question, Ill do the rest tomorrow too tired right now lol





Correct or way off?
Yep, notation is a little funky but the idea is write, a constant sequence will get killed straight away by the operator '. Compare this to the behaviour of a constant function being differentiated :).
 

seanieg89

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Re: HSC 2012 Marathon :)

Just going to check my step 1 here to see if I actually understand the question, Ill do the rest tomorrow too tired right now lol





Correct or way off?
Yep, notation is a little funky but the idea is right, a constant sequence will get killed straight away by the operator '. Compare this to the behaviour of a constant function being differentiated :).
 

Sy123

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Re: HSC 2012 Marathon :)

Yep, notation is a little funky but the idea is write, a constant sequence will get killed straight away by the operator '. Compare this to the behaviour of a constant function being differentiated :).
Alright nice I will see if I can complete this tomorrow

(inb4 detroyed)
 

seanieg89

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Re: HSC 2012 Marathon :)

Alright nice I will see if I can complete this tomorrow

(inb4 detroyed)
Honestly not that difficult, maybe think about how you would try to prove the analogue of this theorem for functions: f is killed by taking finitely many derivatives if and only if f is a polynomial :). Because differentiation is more familiar this should be quite easy, then try to mimic this approach for the less familiar operation going on here.
 

Sy123

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Re: HSC 2012 Marathon :)

Progress

Thats just my progress on Step 3, but I keep running into that barrier, I want to be able to prove that


But I cant because I just end up with:



Am I missing something here?
 

seanieg89

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Re: HSC 2012 Marathon :)

Hint: polynomial degree. Gtg now but will look closer at your work later if you don't get it yet.
 

lgnorance

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Re: HSC 2012 Marathon :)

A point P is marked inside a regular hexagon ABCDEF so that angleBAP=angleDCP=50deg. Find angle ABP.

GL.

PS. Answer is 80deg.
Fwark, this is a good question.

Just did it using complex numbers.
 

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