Menomaths
Exaı̸̸̸̸̸̸̸̸lted Member
- Joined
- Jul 9, 2013
- Messages
- 2,373
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- HSC
- 2013
you're answer should be dependent on 'n' =)0.75?
My bad, 0.75n?you're answer should be dependent on 'n' =)
If n = say 10, then your probability becomes greater than 1My bad, 0.75n?
Oh my god....0.75n?If n = say 10, then your probability becomes greater than 1
Just imagine n to be any other regular number, do it for 5 numbers first, then try to do it for any number n
Oh my god....0.75n?
Shit, I'll think about it this time...My name holds true so far
I'll leave it to you to explain why it is. i.e. I've turned the question into a 'Show that'
[/QUOTE
1. Change cotx into cosx/sinx
2. multiply top and bottom of the fraction by sinx
3. Now you should realise that the differentiation of the bottom equals to top.
Hence the answer is ln(sinx - cosx)
don't be fooled, you will not need to use any 3U knowledge hereI don't think 2 unit learn angle sums...
This proof would probably be accepted at 2U level, same concept is used in loan repayments/annuities etc
I'm sorry Sy I will never doubt you again.don't be fooled, you will not need to use any 3U knowledge here
so the ladder is extendable?