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HSC 2013 Maths Marathon (archive) (6 Viewers)

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Re: HSC 2013 2U Marathon

Sorry about that. :( However, the question didn't really ask for an explanation. Anyway, I tried doing the question above and my proof is a little bit 50/50, but I couldn't think of any other way to do it. IMG_0474.jpg I hope it is sufficient :) Cheers!
 

Sy123

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Re: HSC 2013 2U Marathon

Sorry about that. :( However, the question didn't really ask for an explanation. Anyway, I tried doing the question above and my proof is a little bit 50/50, but I couldn't think of any other way to do it. View attachment 28606 I hope it is sufficient :) Cheers!
That is essentially what I was aiming for, well done.



 
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Re: HSC 2013 2U Marathon

Good question... Took a lot of working out (which probably could have been avoided but oh well) IMG_0482.jpgIMG_0484.jpg ... Also, I wouldn't say my proof is very good but that's how it is haha
 

Sy123

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Re: HSC 2013 2U Marathon

Yes well done, it was the long way however.





Now, differentiate the curves, and find the gradients of each curve at P







===

By the way, that was from HSC 4U Q7 =)
But you can (as you ahve shown) can do it at 2U level, and its good that you were able to solve it.
 
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Re: HSC 2013 2U Marathon

Ah sick! ahah... Yeah, I went the very very long way but I eventually got there... So much quicker ^
 

Sy123

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Re: HSC 2013 2U Marathon

















 
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Re: HSC 2013 2U Marathon

Biggest trek of my life due to a range of mistakes I made initially, but I finally got the answers (I hope :p ) lol IMG_0486.jpgIMG_0487.jpg
 

Sy123

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Re: HSC 2013 2U Marathon

Well done, though I was intending that you didn't refer to the actual trigonometry and just used 't' only, but its all good.

=======













 

SpiralFlex

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Re: HSC 2013 2U Marathon

Change the minus 1 to 1 and there will be real solutions then.
 

HSC2014

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Re: HSC 2013 2U Marathon

Oh does that work hahaha... I assumed it was a typo but i didn't know which part.
 
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