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HSC 2013 Maths Marathon (archive) (1 Viewer)

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Sy123

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Re: HSC 2013 2U Marathon



 

braintic

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Re: HSC 2013 2U Marathon

For a given function f(x), we know that f(1)=3, f(3)=-2, f(6)=5, f ' (1)=f ' (3)=f ' (6)=0, and f '' (x) > 0 for 2 < x < 4, and -ve elsewhere.

Find the area of the region bounded by y=f ' (x) and the x-axis.

[Do not attempt to fit an equation to f(x) or any of its derivatives]
No-one?

(I should have said the function and its derivative are continuous throughout.)
 

omgiloverice

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Re: HSC 2013 2U Marathon

Since I am doing probability in class the rest of you must also suffer





 
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Re: HSC 2013 2U Marathon



Show that the tangent to the curve at is given by

.

If this tangent passes through the origin, find the value of .

Hence find the area of the region enclosed by the curve , the tangent to the curve which passes through the origin, and the -axis.
 
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Re: HSC 2013 2U Marathon

This is my first time on one of these marathon things and I don't know how to use 'LaTex', but does a=e, and is the area (e/2)-1? I'm probs wrong but worth a try :p
 

JT145

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Re: HSC 2013 2U Marathon

yay threads like this exist
 

AnimeX

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Re: HSC 2013 2U Marathon

Should part.ii be: "Hence, show that a^2 = 16 -2v^2" ?
ehh nope, I just had a go at it and part ii) is correct.

you should recheck your working, perhaps you forgot to square the 2 in (-v/2 )^2.
 
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Re: HSC 2013 2U Marathon

This is my first time on one of these marathon things and I don't know how to use 'LaTex', but does a=e, and is the area (e/2)-1? I'm probs wrong but worth a try :p

that's correct.
 

Sy123

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Carrotsticks

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Differentiate both sides and multiply both sides by something.
 
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