motion questions, plz help brain blank. (1 Viewer)

[astroman]

brain just switched off lol on simplest questions soz.

 

[astroman]

.

 

[anomalousdecay]

60 N of force at X. That is the total applied force to the blocks.

Altogether the total mass is 6 kg.

F = ma. a = F/m = 10 m s^(-2)

At Z, we have an acceleration of 10 m s^(-2) and the block is 3 kg.

The tension at Z is 30 N (F = ma), since that is the force applied specifically to that block at that moment.

At Y, we have 5 kg of mass and 10 m s^(-2) of acceleration. So tension at Y is 50 N.


(Don't take my word too much I've been short of luck recently, check with the answers).

 

[astroman]

thanks, theres no answers

 

[anomalousdecay]

thanks, theres no answers

In that case, ask your teacher or wait for another BoS'er to reply back here.

Also, do remember to put the direction for b) and c).

Any way, if you know how to, try resolving it by a free body diagram.

It makes things easier. Or you can just apply what you understand.

 

[astroman]

ur answers were correct dw. everything works.

 

[Drongoski]

I used a different approach - got same answers as anomalous. His method is a lot easier.

 

[anomalousdecay]

I used a different approach - got same answers as anomalous. His method is a lot easier.

You can break it all up into components and do it, but then it gets a bit more complicated.

So just regarding the acceleration here is sufficient.

 

[cub3root]

write down all values:

m1 = 1 kg
m2 = 2 kg
m3 = 3 kg
Tx = 60N
Ty = ?
Tz = ?

a) T = ma

a = 60/(1+2+3) = 10m/s^2

b) Tz = ma
= 3 x 10 = 30N

c) Ty = ma
= (2 + 3) x 10
= 50N