The answer is 1, 3, 5, 7, ... so d can't be 1 and a can't be 11/2.< - equation 1
< - equation 2
Solving simultaneously
< - equation 2
minus < - equation 1x2
-------------------------
, d = 1 and a is 11/2
The Equation 2 here should have 400 on the LHS, because the question says the "next" 10 terms have sum 300, so the first 20 terms in total have sum 100+300 = 400.< - equation 1
< - equation 2
Solving simultaneously
< - equation 2
minus < - equation 1x2
-------------------------
, d = 1 and a is 11/2
The Equation 2 here should have 400 on the LHS, because the question says the "next" 10 terms have sum 300, so the first 20 terms in total have sum 100+300 = 400.
And 20 - 1 instead of 10 - 1.
Thanks lads.Sum of first 10 terms is 100 and sum of next 10 terms is 300, which means sum of the first 20 terms is 400. So you would have:
Solve simultaneously to get a=1 and d=2. Hence, the series is
1+3+5+7+...