The sum to n terms (Sequences and Series) question (1 Viewer)

BlueGas

Well-Known Member
Joined
Sep 20, 2014
Messages
2,448
Gender
Male
HSC
N/A
I need help with this question. The sum of the first 10 terms of an arithmetic series is 100 and the sum of the next 10 terms is 300. Find the series.
 

Silly Sausage

Well-Known Member
Joined
Dec 8, 2014
Messages
594
Gender
Male
HSC
2014
< - equation 1
< - equation 2
Solving simultaneously
< - equation 2
minus < - equation 1x2
-------------------------
, d = 1 and a is 11/2
 
Last edited:

BlueGas

Well-Known Member
Joined
Sep 20, 2014
Messages
2,448
Gender
Male
HSC
N/A
< - equation 1
< - equation 2
Solving simultaneously
< - equation 2
minus < - equation 1x2
-------------------------
, d = 1 and a is 11/2
The answer is 1, 3, 5, 7, ... so d can't be 1 and a can't be 11/2.
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
< - equation 1
< - equation 2
Solving simultaneously
< - equation 2
minus < - equation 1x2
-------------------------
, d = 1 and a is 11/2
The Equation 2 here should have 400 on the LHS, because the question says the "next" 10 terms have sum 300, so the first 20 terms in total have sum 100+300 = 400.

And 20 - 1 instead of 10 - 1.
 

VBN2470

Well-Known Member
Joined
Mar 13, 2012
Messages
440
Location
Sydney
Gender
Male
HSC
2013
Uni Grad
2017
Sum of first 10 terms is 100 and sum of next 10 terms is 300, which means sum of the first 20 terms is 400. So you would have:


Solve simultaneously to get a=1 and d=2. Hence, the series is

1+3+5+7+...
 

BlueGas

Well-Known Member
Joined
Sep 20, 2014
Messages
2,448
Gender
Male
HSC
N/A
The Equation 2 here should have 400 on the LHS, because the question says the "next" 10 terms have sum 300, so the first 20 terms in total have sum 100+300 = 400.

And 20 - 1 instead of 10 - 1.
Sum of first 10 terms is 100 and sum of next 10 terms is 300, which means sum of the first 20 terms is 400. So you would have:


Solve simultaneously to get a=1 and d=2. Hence, the series is

1+3+5+7+...
Thanks lads.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top