state rankBecause expecting the unexpected makes the unexpected expected
Q.E.D
WrongBecause expecting the unexpected makes the unexpected expected
Q.E.D
That is a good way to analyse it using physics principles. What I was looking for was something along the lines of sin^2(x) can essentially be written in terms of -cos(2x) and thus we actually walk down to a road of standard derivatives and integralsWould this suffice?
By the Hockeystick Identity for Combinatorial summation, the result is immediately true.Easy question
 = \binom{n}{2})
I confirm that your working is correct and the book's working is incorrect.Think there has been a typo with this solution for part (b) for Circle Geometry
This was the books answer:
I think the answer should be:
If someone could confirm that would be great.
Is that by the use of Mathematical induction?Expression subject to massive inaccuracy...
^3\sum_{k=0}^{n}{\frac{1}{(k!)^2\left((n-k)!\right)^2}}=(2n)(2n-1)\dots n)
Equating the first method's x to 6 isn't quite right, it should be to -6. This is because by choosing epsilon = pi/2, you made it so the particle starts at the origin but moves towards the negative side first, so you should equate the x to -6. This should then yield the right answer. In fact this can be seen without redoing the Q.: by symmetry of the function (it is odd if you check it), if you equate it to -6, since it attains +6 at t = -1.02, it attains -6 at t = +1.02 (odd function). So the answer is 1.02 (rounded of course).Could someone please explain why I'm getting a negative answer when I use cosine in the following SHM? When I use sine, the answer is correct.
