nowomansland
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nevermind…theyre currently re-checking that soln so it migth be one ppt
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nevermind…theyre currently re-checking that soln so it migth be one ppt
It looks like he checked using molar solubility. if the math is all correct then it should be two ppt. I was under the assumption that far more Mg2+ will precipitate out, but if the math says otherwise then both precipitating out should be correct.i put both will ppt asw and catalyst says the same. also who tf thinks of a bar graph wtf i just did line of best fit and called it a day? View attachment 50279
FARK I THOUGHT OF IT BUT AT THE VERY END I THOUGHT SURELY FKN NOT BRO WHO TF WOULD PUT BAR AND IT WAS BAR SOMEONE KILL MEguys ion think we need to have a bar chartsurely fucken not cos who is thinking of that
yeah i did the same thing and got the same values and everything so not sure why that wouldn’t workIt looks like he checked using molar solubility. if the math is all correct then it should be two ppt. I was under the assumption that far more Mg2+ will precipitate out, but if the math says otherwise then both precipitating out should be correct.
Concentrations are all still the sameWHY TF WOULDNT ARGON AFFECT EQUILIBRIUM
FKKKKKK MEConcentrations are all still the same
it wasn’t asking if the eq position changes tho it was if temp of system will change so i’m really confusedConcentrations are all still the same
they were asking if the addition argon would cause the temp of the system to change - so theyre assuming that the temp change is from the equilbrium shifting in heat absorbing end. rxn or heat releasing exo. reaction; this means that for a temp change to occur, the equilibrium position must changeit wasn’t asking if the eq position changes tho it was if temp of system will change so i’m really confused
but the pressure caused by the species of the equilibrium doesnt changebut the argon would increase overall pressure which increases T right?
equilibrium shifts to pressure are only when the pressure of the actual species in the equilibrium changesbut the pressure caused by the species of the equilibrium doesnt change
Nvrmind I think theres an error. the person who wrote the solutions says that Mg2+ remaining after solution = 0.006 - x where x is the molar SOLUBILITY. Wouldnt x be the amount remaining in the solution? This would mean 1.11 x 10 ^(-4) M of Mg2+ would remain in the solution. Definitely not 0.006 - x. Of course this is not possible, since we at maximum, can ppt out 0.005M due to Mg2+ being the excess reagent in the OH- and Mg2+ reaction. So this cannot be correct. If we assume a complete reaction, then 0.001M of Mg2+ is remaining. Then there should be 1 ppt, not 2.i put both will ppt asw and catalyst says the same. also who tf thinks of a bar graph wtf i just did line of best fit and called it a day? View attachment 50279
YESYSYYSYSYSYSYSYSYSYYYYSNvrmind I think theres an error. the person who wrote the solutions says that Mg2+ remaining after solution = 0.006 - x where x is the molar SOLUBILITY. Wouldnt x be the amount remaining in the solution? This would mean 1.11 x 10 ^(-4) M of Mg2+ would remain in the solution. Of course this is not possible, since we at maximum, can ppt out 0.005M due to Mg2+ being the excess reagent in the OH- and Mg2+ reaction. So this cannot be correct. If we assume a complete reaction, then 0.001M of Mg2+ is remaining. Then there should be 1 ppt, not 2.
I just said that because its a sealed pressure vessel then adding anything will increase the pressure, one reaction had a higher molar ratio than the other so by le chat the system will favour the reaction to decrease pressure which subsequently was exothermic (or endo I can't remember)equilibrium shifts to pressure are only when the pressure of the actual species in the equilibrium changes
ohNvrmind I think theres an error. the person who wrote the solutions says that Mg2+ remaining after solution = 0.006 - x where x is the molar SOLUBILITY. Wouldnt x be the amount remaining in the solution? This would mean 1.11 x 10 ^(-4) M of Mg2+ would remain in the solution. Definitely not 0.006 - x. Of course this is not possible, since we at maximum, can ppt out 0.005M due to Mg2+ being the excess reagent in the OH- and Mg2+ reaction. So this cannot be correct. If we assume a complete reaction, then 0.001M of Mg2+ is remaining. Then there should be 1 ppt, not 2.
But is that not assuming that 100% will react one way and that it could be either precipitate or a mixtureNvrmind I think theres an error. the person who wrote the solutions says that Mg2+ remaining after solution = 0.006 - x where x is the molar SOLUBILITY. Wouldnt x be the amount remaining in the solution? This would mean 1.11 x 10 ^(-4) M of Mg2+ would remain in the solution. Definitely not 0.006 - x. Of course this is not possible, since we at maximum, can ppt out 0.005M due to Mg2+ being the excess reagent in the OH- and Mg2+ reaction. So this cannot be correct. If we assume a complete reaction, then 0.001M of Mg2+ is remaining. Then there should be 1 ppt, not 2.
