Recent content by Casper_18

Has anyone got any yeats essay topics? I have done all the ones that I have been given.

I have used the SHARP calculator since year 7, the exact same one. I dont Get math errors when I type in -8^(5/3)/5 though. The sharp calcuator is a very good calculator. Although I have found that Casio are better at calculating fractions of larger decimals.

Ramanujan

Correct and if you remember your index laws anyway x^(2/3) you are squaring and then taking the cube root so you are taking a positive cube root anyway. because any number squared is positive in the real number system.

when you do this you have to consider the graph. Seeing as though they are not asking for an area and what you are integrating is an even function. i.e. F(x) = F(-x) then it becomes: \int_{-a}^{a}f(x) = 2\int_{0}^{a}f(x) so in your case \int_{-8}^{8}x^{\frac{2}{3}}dx...

Because the prac that you did on it is an essential prac and they can ask you about it in the HSC.

What and where is NCAP??

I wasn't expecting anyone to analyse it for me, I Have done that myself. But thanks for the other post that was helpful (#5).

I found this text in another thread I am going to use it I just need some things to talk about other than the obvious contrast between the cells. And some background on the conflict would be nice :)

I want to be an actuary. What do I need to do?

Thanks, that helps me out heaps. :)

I am having a bit of trouble For examble a particle is moving downards with a resistance proportional to v² In this part you get an equation that looks like: ma = mg - mkv² What I dont understand is why the resistance is equal to mkv² when there is...

y= 3cos^{-1}2x\\ \frac{y}{3}=cos^{-1}2x\\ cos\frac{y}{3}= 2x\\ x= \frac{1}{2}cos\frac{y}{3} and then just use the equation in terms of x to draw your graph and rember the restricted d & r when you draw it.

I am learing german at the moment. Great language but has some stupid things too.

Maybe she is attention-sexual??