Recent content by nelsonzheng

If I'm not mistaken, the chemical reactions in this dry cell are much more complex than what is required by the HSC. However, as stated in Wikipedia: So according to that, NH₃ is not a spectator ion, but are in fact a part of a secondary reaction, if that's what you were asking...

Yes, if the train continues to accelerate at a greater or equal rate to the moment depicted in this picture then yes, you're right. However, this question doesn't specify =(

yeah, i simplified it somewhat but that would be how things would work. Why don't u go get a magnet and a solenoid and play with it?

Have a watch of this video: A current will be induced only when there is a change in magnetic field or in this case a relative movement between the solenoid and the magnet. When the North pole of a magnet moves towards a solenoid, it will induce a current, giving rise to a North Pole at the...

oh my bad, cheers mate heres the new graph: (Hope i didnt make more mistakes lololololol)

y=x+1+1/(x-1) Let's split this graph into y=x+1 and y=1/(x-1) y=x+1 is a straight diagonal line with y intercept of 1 and a positive gradient. (this doesn't really change the question) y=1/(x-1) is a hyperbola with an asymptote at x=1 Then you add the 2 together as seen below: Hope that...

Blue line: original plot Red line: original plot divided by 2, thus half the amplitude Yellow line: (Red line)^4 Thus, no 16. You can find the maximums just by subbing in some numbers into the calculations u did for graph 1. then just guess the general shape of the curve

Given that you have already plotted graph 1, you can see the relationship between graph 1 and graph 3:

1) y=2x/(x^2+1) 3) y=x^4/[(x^2+1)^4] Your basically applying ^4 to graph 1

Thanks for clarifying. I was merely producing a graphic to help people understand.

amirite? (might've exaggerated how far forward the ball goes)

Just do it, chem is awesome