Recent content by P.T.F.E

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    Section II - Short Answer

    yeah i said costs: tourism, economic interaction for the town decrease as they will be now bypassed, environment in building bypass such as logging etc. benefits: noise pollution reduction, reduction in air pollution, Increase in infrastructure increases development for economy...
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    Share your Multiple Choice answers

    How is 10 (C), i got (D)
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    Thoughts?

    Share your thoughts on the exam? I personally walked out early and believe i may get a state ranking. Easy :guitar:
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    CSSA Economics 2013

    Isn't it (CPI year 2 - CPI year 1 )/ CPI year 1= 0.05 Real GDP takes inflation rate of 5% into account, 5% of 840 = 42 therefore Real GDP = 798?
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    Questions: CONICS, POLYNOMIALS, VOLUMES

    Assessment coming up involving these conics, polynomials and volumes. If anyone has any questions on these chuck them my way. CHEERS :headbang:
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    Hsc dates

    Times like these, i wish i was asian.
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    Hsc dates

    Anybody else have: Tuesday -MX2 Thursday- Mx1 Friday- Eco Brutal as, Eco's content is dense as.
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    In what year was Gwen Harwood's 'Father and Child' Written

    In what year was Gwen Harwood's 'Father and Child' Written. Please and thank you
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    Help.

    For what values of m does the line y=m(x+1) have no intersection with the parabola y=2x^2
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    preparation for physics course 1st year(no physics for hsc)

    If you are doing PHYS1121, which is physics 1A, then despite what they say there is a lot of assumed knowledge. I didn't do Physics HSC and I am happy to say I passed but it was tough ( I had to do higher for my degree). I didn't realise how much knowledge everyone else already had on me, and if...
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    Weird question

    It is just a circle with radius of 3, center (4,3) on Argand diagram
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    higher derivatives q

    F(X) = x . (3x -4)^1/2 F'(X) = (3x - 4)^1/2 + 1.5(3x - 4)^-1/2 F''(X)= 1.5(3x - 4)^-1/2 - 2.25 ( 3x - 4) ^-3/2 F"(2) = 1.5 * (1/sqrt 2) - 2.25 * (1/sqrt. 8) = - sqrt 28.125 I THINK... HOPE IT HELPS
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    Locus Q help :(

    20. |(ax+ by + c)/sqrt. a^2 + b^2 | - recall perpendicular distance formula. distance =1 therefore this always has to = 1. |(12x-5y-1)/sqrt.169|=1 (12x - 5y - 1) / sqrt.169 = 1 or (12x - 5y - 1) / sqrt.169 = -1 12x - 5y - 1 = sqrt 169 or (12x - 5y - 1) = - sqrt 169 12x -5y - 14= 0 , 12x...
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    How Many Classes

    Lucky I have 14 Ext1 classes every 2 weeks and 6 Ext2 :/ all 1hr lesseons
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