Recent content by Qeru

U sound like SylviaB lol.

But what about stuff like Poker and other card games. these are also considered sports yet involve no physical exertion?

You know what I actually agree with you for once, this is the first time you actually made a decent argument.

I wonder who I should trust the international olympic commitee, or some random guy on BoS

C+iS=\int xe^x \cos{x} dx +i \int xe^x \sin{x} dx C+iS=\int xe^x (\cos{x}+i\sin{x}) dx C+iS=\int xe^x e^{ix} dx \quad \text{ By Euler's identity} C+iS=\int xe^{(1+i)x} dx By IBP we get: C+iS=\frac{xe^{(1+i)x}}{1+i}-\frac{1}{1+i}\int e^{(1+i)x} dx...

Yeah agreed the graphics literally look like those crappy phone games

You could always nuzlocke it

Another Idea is to maybe find the vector projection which allows u to find the perpendicular and find the area of the triangle that way. Not bothered to Latex it tho.

Yeah looks good I dont see any issues with your working. @csi can you send a screenshot of the original question?

This is an excellent video related to your problem of 'satisfication' of learning: . Simply put Faraday's law states an EMF is produced when a coil experiences a change in flux, any further 'whys' will simply leave you unsatisified as they simply aren't at an HSC level.

Wow thats really cool I just realised you did 140/13 since the RHS has 13^4 in the denominator, will that always output a 'nice' answer for k?

How would you do the BSc without atar? Would you need to do some other exam first?

How long did that take you to type out

Assume a,b and c are integers. We know from pythagoras: a^2+b^2=c^2 and (a+1)^2+(b+1)^2=(c+1)^2 a^2+b^2+2a+2b+2=c^2+2c+1 c^2+2a+2b+2=c^2+2c+1 2a+2b=2c-1 a+b=c-\frac{1}{2} But addition is closed for the integers so the LHS must be an integer but the RHS is clearly not so...