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Lost all motivation to play anything but lee-sin If i'm last pick, pretty much a queue dodge, even if it costs 10 lp +

Ok thanks! I have another question.. Sketch the curve y^2 = x(x-1) Here is how I approached it: Firstly, y = +- sqrt(x(x-1)) so the domain would be x <= 0 and x >=1 And after differentiating, there turns out to be no stationary points x intercepts at 0,1 y = 0 Now here's the thing; I don't...

Hello, How do I sketch: 1. y = f(|x|) 2. y = |f(x)| 3. |y| = f(x) For the function: http://imgur.com/P2xfTr5 I have a couple things that need clarification: *Is it better to find the equation of the function and somehow continue accordingly? or is it better to recognise the nature of each...

Yeah, me too. Someone boost me pls :( LoL: joshmosh2

Anyone up for a BOS team?

The terry lee worked solutions look alright

Yeah but the problem is I don't know the content yet :l

Hello, I have been relying on my tutor to learn ahead of my school content, but there is now a two week break (school holidays) Any suggestions on effective methods to self-learn content, specifically 4U? I think i'm more of a visual learner (diagrams, step-by-step solutions etc) For some...

Yes please!

Mine looked like that too. If the min of the function was placed much lower, for example like this: http://imgur.com/m8fDWP5 Would that correlate to a steeper part for that quartic?

Also, one more question. This graph is f(x), so what would the gradient of the function look like? http://imgur.com/9lUZrv4

Weirdly enough, I had exactly the same question in my prelim test today, it was basically this a/x-2 + b/x-3 For the polynomial question, since it's a double root, P(1) = 0 but also P'(1) = 0 So by solving simultaneously, I got m = -68 and n = 90 If you sub the function into a graphing...

Oh I forgot, the polynomial passes through (1,2) .. LOL

Cool, that's similar to how I worked it out, but instead of P(x,y), I used P(acosx,asinx). Still equates to the same answer tho.

Yes of course, but I mean using the fact that x^2 + y^2 = a^2 I forgot to say, but it was a 'hence' question

P(x) is an even function and passes through the point (1,2). What is the remainder when P(x) is divided by (x+1)? The possible answers were a) 0 b) -1 c) 1 d) 2 What I thought was that since P(x) is an even function, P(-1) = P(1) so the answer is 1? Not 100% sure about this one. Any help is...

No need to buy when you can take the same idea but change some of the values hehe

Hey, that polynomial question is quite interesting. Not 100% sure, but does the solution include P(1) = 0 and also P'(1) = 0 (since double root) so my final answer is P(x) = 2(x-1)(-32x^3+11x^2+17x+6) Also for the next question, do you mean (a/x+2) + (b/x-3) ? If so, looks like an identical...

Circle geo is usually done in yr 11 and is an extension topic only. If you haven't done it this year, you will do it next year.

I heard daily revision is good. Probs self learn part of the yr 12 MX1 and 2 syllabus, and maybe try and finish the first "Space" topic for physics. BUT everyone is suggesting breaks instead of studying.. so...