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A ship bearing 036 degrees is 5500 metres due south of a lighthouse Apparently, the 5500 metres is the hypotenuse of the diagram? Can someone please provide a diagram so I can understand it better thanks :drink:

In circle geometry, if you are to draw some lines, for example, 3 parallel chords, would it be viable to construct one of your chords through the centre and use some of those properties? OR Is it that you can't assume that the parallel lines are through the centre, and therefore, all lines...

Two chords AB and CD intersect within a circle at X. Prove that angle AXC is equal to the sum of the angles subtended at the circumference by the minor arcs AC and BD.

or you can just do them in 10 sec

If I have already proven that a shape is a cyclic quadrilateral, where would the centre of the created quad be? I recall somewhere that the centre is the intersection of altitude lines (perpendicular to opposite sides of shape). I was also thinking that the angle at the centre would be twice the...

Find the length of the common chord of two intersecting lines whose radii are 15cm and 13cm and whose centres are 14cm apart. So I drew up the diagram, with the chord creating two right angled triangles I labelled one side x, and the other 14-x to find half of the length of the chord...

So with two triangles, to find any ratio, you would need at least 2 known sides?

Hold on a second, I'm confused with this. Subbing the values into the equation doesn't work? Did you use double angle formula for 2y? What did you do wrong exactly 0.0

To prove similarity using the 'one corresponding pair of angles are equal and two pairs of sides are in proportion' Can you prove similarity with one or two unknown variables within the proportions? If so, does that mean you can consider them 'similar' even though some corresponding sides are...

schedule - 6-8 hours weekdays 5-6 hours weekends of procrastination

You're right, but apparently there are slight differences in both. Mind = blown

WAIT! ASA also exists, no wonder i got them confused. Most textbooks don't even mention this but I guess I can't call it AAS if the side is included within the angles. Woah.. OP

Thanks, I was confused, as some websites say two corresponding angles and one non included side, and some say two corresponding angles, and an included side.

Does proving aas require any specific set of angles and sides? or is it any two pairs of corresponding angles and one pair of corresponding sides?

J and C for the exercise. I also use MIF and cambridge

Ahh yes! included angle is the bit that got me. The diagrams had all the corresponding sides, and the corresponding angles are equal, however they were not included angles, therefore can't prove congruency. THAT'S OP!

In my exercise, two corresponding sides and one corresponding angle is the same, however, one appears to be slightly taller than the other. So is sight the only way to determine questions like these? if so, there might be one or two questions that i can get wrong without realising.

Yes, I have learnt them. The exercise I am doing right now is to state if they are congruent or not, not prove congruency. You are basically given all the information. The problem is, some of them seem that their 'supposed' corresponding sides and angles are equal. The one I had wrong had two...

Hey, is there any technique that I can use for complete accuracy in determining whether triangles are congruent or not? As i went through the answers I got one wrong. I am determining them by sight and am trying to rotate them in some way. There must be a better way!

Thanks, but how would I do question 2?