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kinda feels like the HSC for me again llol

That would imply that \\ \sin x + \cos x = 0 which means that the solutions generated would not be the same, so maybe the question is wrong

put it this way, it just gets worse.

lol what that doesn't seem valid, you would have to somehow end with the line t1 = t2 (assuming that the question is right) Yeah just wondering, is this question right?

be aware that your 4U marks is also taken into account when the 3U ranks are distributed (since there would be around 10-20 getting 100% in the externals)

Re: MX2 Integration Marathon For parts i and ii I1 = \int_{0}^{\frac{\pi}{4}}\frac{1-cos2x}{sin2x} \\ = \int_{0}^{\frac{\pi}{4}}\frac{2sin^22x}{sin2x} = \int_{0}^{\frac{\pi}{4}} tan x = ln(\sqrt{2}) \\ \\ \\ I^{2r+1} - I^{2r-1} = \int_{0}^{\frac{\pi}{4}}...

you got that wrong, let the roots be a,b,c,d and ab=cd and as the other said use all of the root properties of the polynomial

To get state rank you need talent, dedication, and luck on the exam day.

Haha nice question, This actually consists of BOTH AP and GP First you separate the series into 2 parts , the sum of the first 20 terms in (n-1) i.e (0-1-2-3-....-19) = 20/2(0-19) = -190 then I find the sum of the first 20 terms in 2^n which is 2+ 2^2 +2^3 + ... 2^{20} = 2(2^{20}...

Yeah because like i said you got an equation in terms of tan x. so x can't be pi/2 in those lines as it's undefined. I'm assuming you used general solution to get x = \frac{2k\pi+\pi}{6} which would generate x = pi/2 , or how else did you get x = pi/2?

\tan(k\pi+ \frac{\pi}{2} ) (where k is an integer) is undefined, and the quadratic equation you got is in terms of tan x so it's not possible to obtain solutions x = k\pi+ \ \frac{\pi}{2} even though it's a solution to the original equation.

going on the ski trip with the BSOC YEAAHHH

hehe 1141 i wonder in Q3 v, who forgot the open circle at x=0 :P

rawrrrrr

ahhhh Drifting95 can do the honours

yay

it's not equal to anything.... so you can't "solve" \frac{5}{x^2-1} - \frac{3}{x-1}

pics or link brah

Rawrrrrrrr

YOYO