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well yeh sometimes I wonder if i exist....

Na Cambridge 4u is not good. Terry Or Ptel and Coroneos has range of exam style questions

Well thats is not quite true. See wentworthville sydney bombing that happened recently in a suburb 1km off my house. It completely destroyed the shop but no suicide bombers.

Hey guys, I am just wondering about the exams. Scenario is: someone has learnt a topic and has a topic test that is very hard and if he doesnt do good at it, he bears serious consequences. It is a 4U topic. Question: i) Should he do the past papers from his school to prepare for the topic...

Oh ok. Right that is what you mean HSC2014. Hahaha I took the wrong corresponding sides cos no diagram. So sorry :). . Yeah that is how u do it hs2014. See if you get anywhere from continuing my way... :_( ....

He is going for a Phd... you must expect that/. Well any of guys do HSC papers like 1995 or something?

Well Proofs may be needed a lot so familiarisation is required and also understanding. Overall its hardwork and dedication> :) Cheers and Good Luck

Hey guys me and my friend was having a discussion on the theory of ac generators. I have finished the all core modules theory but applications still remain and he has done even the option topic. Well which is correct: 1) Slip rings with shaft act as commutators in AC generators. (what he was...

well are these 2 good ways fizzycyst? a = gm2/r^2 therefore as lim r -> infinity , the gravitational acceleration approaches zero. This means the acceleration due to gravity towards centre decreases therefore the velocity away from the centre would increase and again supporting that as...

Wait they tell you what to do? Shouldnt they though?, since the students are exposed to using any of the 3 possible methods for partial fractions, and they might want to test them on one. Well if you get what I mean.

Hi guys i have a complex number test on the whole topic soon. How do I revise for it? It is on saturday. Please provide all ideas. :confused:

Np. :) Well its ok, i mislooked what you did.

Even I didnt get you. ^ sorry ^

U did sillies a1079atw. Please check z^2= 1+....... and then u continued on with z = 1+.... Like this? ((z-1)/(z+1))^6=-1 (z-1)/(z+1)= [cis((2kpi+pi)/6)] Now z-1= (z+1)(cis ((2pi+pi)/6)) z-1 = zcis ((2kpi+pi)/6))+ cis(cis ((2pi+pi)/6) Since z is factorable z(1- cis((2kpi+pi)/6)) -1 = cis...

Yes it looked as so to me but just wanted to confirm.

Can this question be done without substitution? If so please if possible show me how. Thanks

Well hahah then thats possible with the square at the top. In your first image you didnt have the squared symbol at the top. Well Drongoski Did it already.

Uhhh.. your tastes are not so good....? series and sequences - worst...... The whole Integration Topic = best.

? Damn ? Heroic? Panda, Sy123 where r u? Can u tell me if Terry Lee or RealiseNothing is right?

Really Complicated even with substitution. That 4u Extension? If so I havent done it yet. wow yesterday you were on 3 unit. Nice progress. Good Luck and sorry.