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ahh...yeh, and also the cultural revolution of the Mao years (which meant that all the rich and educated people were persecuted)

i think it's a phenomenon of the last 30 years - as a result of the poverty problems in asia in the 19th - 20th century. before then, literature was the main focus of education in asia. so that's probably why.

Prove case for n=1 7+13+19 = 39 which is multiple of 13 *tick* Assume case true for n= k (k is odd) then let 7^k + 13^k + 19^k = 13M (M is a positive integer) Then for n=k+2 (the next odd integer) 7^k+2 + 13^k+2 + 19^k+2 =...

People who've done well in HSC "chemistry" are getting pretty lost in first year uni chemistry. This is because we at NSW are getting taught NOTHING...well a lot of bullcrap. When you get to my stage, you'll realise that other states are getting taught much more real chemistry than we are...

To generalise, a catalyst provides an alternate mechanism for the reaction to take place. The new pathway has a lower activation energy, and since more molecules are going to have enough energy to react in this pathway, the reaction SPEED will increase. The equilibrium position won't change...

Re: Re: need help with log prob. 2y^2 / log5 - 9log5 = 3y 2y^2 -3ylog5 - 9(log5)^2 = 0 Ok using the quadratic formula this time: y = (1/4)[3log5 +- sqrt(9(log5)^2 + 72(log5)^2)] = (1/4)[3log5 +- 9log5] = (1/4)[-6log5], (1/4)[12log5] = -(3/2)log5, 3log5

It's a change-of-base problem, based on the rule: log(base y)x = logx/logy So 2log(base 5)x - 9log(base x)5 = 3 2logx/log5 - 9log5/logx = 3 Use substitution y = logx 2y^2 / log5 - 9log5 = 3y (2y + 3log5)(y/log5 - 3) = 0 y = 3log5, -(3log5)/2 logx = 3log5, -(3log5)/2 x = 5^3...

Considering complex numbers as vectors, with length and direction. The argument describes the direction. It is defined as the angle made anticlockwise to the positive real axis. As you can see, 0 is the zero vector (a special case) length zero, and undefined direction. Thus it has...

When you integrate something indefinitely, you get a whole set of answers that vary by the constant C. No exceptions. An integral is not the exact opposite of a derivative.

"PB^2 = PA . PC" Whenever you see a ratio like this, think SIMILAR TRIANGLES. If you notice, the tangent - secant theorem is just a result of similar triangles. Now a general rule for math extension questions: use the previous result if you can. Given <PBA = <PCB (the proof of this is...

Add the restriction x >= 0 and you should be fine

Re: Re: Re: haha.. ahh...the principle of comparative advantage... that's why i'm glad i dun have english nemore. With med I'm guaranteed neva needing to write complete sentences.

Re: haha.. uhh...nope i dun plan to study any more maths after S1 2003, because I don't need it for med. O well :(

the 4 med subjects + maths1141

! coincidentally i have a 1141 test on thursday with the tutor by the name of daniel chan.... it's a small world

Re: haha because their tutors are university tutors, who don't bother with Hsc stuff

Hint? I think this might be useful: sin(n-1)@sin@ = cos(n-1)@cos@ - cosn@

maybe we should throw some of these posts into the buy / sell forum

Let A, B, C, D represent 1, z1, z2, z1z2 respectively. In triangles OAB, OCD: angle OAB = angle OCD (arg(z1z2) - arg(z2) = arg(z1) - arg(1)) OB/OA = |z1|/|1| = OD/OC = |z1z2|/|z2| hence OAB similar to OCD (equal angle between two pairs of sides of equal ratio.

The question translates to: find the region where z is closer to the point 1 than to the point -1. Thus it's the region {x,y| x > 0}