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Ask your marking teachers

u=x^4+1 du/dx=4x^3 Int [x^3(x^4+1)^2] dx = 1/4 Int (u^2) du =1/4*(u^3)/3 +c =[(x^4+1)^3]/12+c

it's supposed to be an integral sign

Explain in detail the balance of payments, and Australia's balance of payments performance

they cut way too much out

That makes it even worse. A hard test means that there WILL be variation in marks between students, but not due to the mathematical ability of the student, but rather how smart the student's friends/family/contacts are.

yeah I'm not pissed off at you, anybody who cares about their marks, including me, would have done the same thing, but it's stuffed up how schools give these assessments. The whole purpose of assessments is to differentiate between students, and with assessments like these you're gonna get 99%...

What may be easy for some may be hard for others. Think about what you're interested in, what information you can get easily (like do you know any religious authoritative people who you can interview, are you involved in any religious communities that is willing to be interviewed? etc etc)

still yet to start topic 2, won't start till next yr coz it's holidays for me now

This pisses me off. A hand-in maths assessment... people are just gonna get their family/friends/BOS to do Qs that they can't do. I know that I would have done the same thing if I was in that situation but it's stuffed up how schools give these assessments. I feel sorry for anybody who doesn't...

it's pretty unfair to do Qs on the assignment for her.

Find the points of intersection by solving simultaneous equations, then just put those points as your limits of the volume formula.

what???? a hand-in assessment for maths?

MATHEMATICAL INDUCTION: n ∑ 3^-r = 3^n - 1 ÷ [2(3^n)] r=1 When n=k+1, LHS=3^k-1/[2(3^k)]+3^(-k-1) =(3^k-1)[3^(k+1)]+2(3^k)]/{2[3^k][3^(k+1)} =[3^k][3^(k+1)-3+2]/{2[3^k][3^(k+1)] =[3^(k+1)-1]/{2[3^(k+1)]} =RHS

Find the acute angle between the curve f(x) = x² -1 and the line g(x) = 3x -1 at their two points of intersection. Equs meet when x=0 or 3 f'(x)=2x f'(0)=0 f'(3)=8 g'(x)=3 tan @=3 or 5/23 @=tan^-1 3 or tan^-1 (5/23)

What is the obtuse angle between the curves f(x) = x² - 4x and g(x) = x² - 12 at the point where they meet. Equs meet when x=3 f'(x)=2x-4 f'(3)=2 g'(x)=2x g'(3)=6 tan @=|4/(1-12)| @=tan^-1 (4/11) Obtuse angle = 180-tan^-1 (4/11)

It's aligned marks before scaling

I think he's talking about the band 6 list

How does that work? Different ppl do different subjects

6P2/2 = 15