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simple interest I=PRn

how did you get sinx/(1-(sinx)^2) = -3.75??

its Q7 iv in the Independent paper 2004 but the answer showed as 1/2(f(-1) + 4(f(0.5)+f(-0.5)) +2f(0) + f(1))... thats why im confused

i am still confused.... so for example x=-1, -0,5, 0, 0.5, 1 using 5 values of simpsons rule shouldnt i do (0-(-1)/6 * (f(-1) + 4f(-0.5) + f(0)) + (1-0)/6 * (f(0) + 4f(0.5) + f(1)) ????

CD^2 + CE^2 = DE^2 CD^2 + (CE+EA)^2 = DA^2 CD^2 + CE^2 + 2CEEA + EA^2 = DA^2 DE^2 + 2CEEA + EA^2 = DA^2 CE=EA (diagonals bisect each other in parallelgram) DE^2 + 2EA^2 + EA^2 = DA^2 therefore DE^2 + 3EA^2 = DA^2

in the trial I got 64%

I dont understand what you guys are talking about... i thought simpsons rule is (b-a)/6 * (F(a) + 4F((a+b)/2) + F(b) whats h/3???

goto the resource page of 2U, there is a copy of the answer

where can you get the paper?

since today's paper was apparently harder compared to last years, does that mean it will be scaled even higher?

shitest paper i have ever seen, good bye uni

sorry i beat all of you:D

yeh, i think so :p the table that you will get in the exam

31b2, one factor that will affect the rate of the electrolysis is the concentration of the electrolyte. the more concentrated the electrolyte, the more ions there are to migrate through at a faster rate, thus the greater the rate of the electrolysis as i havent done this experiment so i cant...

31d2, you will just need to compare the standard potential of cooper and aluminium to the metal you answered in part 1, eg iron. plastic wont help prevent corrosion and Fe will still corrode so that one is out then you compare the reduction potential of copper and aluminium to Fe and see...

if you need an answer to a particular question i can help

do you get marks deducted for not writing the state in a chemical equation?? How to tell if something is aqueous or liquid?? i always get mixed up

yeah n=cv is more convenient and my teachers all liked this

N2 + 3h2 <---> 2nh3

weigh?? our teacher never told us to weigh it.. just observe and see if there is rust forming on the surface through out the experiment