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NOx: - Electrical devices - Combustion of fuels - Bacteria SO2: - Combustion of fuels - Volcanoes - Extraction of metals

n OH- = 0.2 * 30 * 10^-3 = 6 * 10^-3 mol n H+ = 0.1 * 40 * 10^-3 * 2 = 8 * 10^-3 mol --> n H+ in excess = 2 * 10^-3 mol --> [H+] = 2* 10^-3/70 * 10^-3 = 1/35 --> pH = 1.54 Yep, sorry that I always forget to sum the last volume. ---- Delta H = 300 * 4.18 * 20.5 = 25707 J =...

Finger cross for a cut-off of 100+. If it's 110+ like those 6 maniacs suppose, I'll suicide! Or I hope that they do give half-marks!

Um, why are they dissolved? Isn't it ice?

Um, why is it Chem to be 'jack in the box'? Supposing you're right, I'm expecting a damn awesome scaling this year. YAY!

Tho I'm feeling there might be something unexpected in Chem this year, the way people are finding Physics easy gives me a doubt.

I suppose 'purify' includes 'sanitize' and 'filter'.

I think we miscommunicated here. It's why I asked you to define 'neutralization'. To be concise and precise, it's the complete reaction between H+ and OH-. The misconception met with titration is that it's not always a neutralization when referring to a pH of 7. When you neutralize a...

'Cuz I want to start off with 1g of Pb and it's present in every 1.6g of Pb(NO3)2. You need to simply work out the ratio between their masses.

One strip of each metal (Zn and Cu), are placed into their corresponding nitrate solutions (Cu into Cu(NO3)2) which are contained in 2 100mL beakers. A U flask containing KNO3 solution with two cotton stoppers is dipped into these two solutions (one head in each). Using electric wires and a Volt...

n H2SO4 = 2* 10^-4 --> n H+ = 4 * 10^-4 n NaOH = 15.6 * 10^-4 = n OH- --> n excess OH- = 11.6 * 10^-4 mol york, you're right. [OH-] = 0.0504... --> pOH = 1.3 --> pH = 12.7 = 13 (2.s.f.) *So embarrassing*

n citric = 10^-4 mol --> n H+ = 3* 10^-4 mol n NaOH = 3.6* 10^-4 mol = n OH- H+ + OH- --> H2O --> n excess OH- = 0.6 * 10^-4 [OH-] = 0.2727... --> pOH = 0.564... --> pH = 13.43... = 13 (2 s.f.) Acid rain's impacts on SOCIETY: - Damages to buildings, marbles, statues...

I can't choose any of the poor choices above. Why don't just give 3 basic options? Anyhow, as long as you know how to extend and apply it, it's actually quite good.

NOOOOOOOOOOOOOOOOOO! But I can't wait to go to the blockbuster and rent my favourite movies. Gosh!

Only repetition is considered here, I suppose. Trying a different method should be to assess the validity. Two methods giving a similar results don't give you much anything. We then have to assess validity and reliability of the new one AND of the old one. Very troublesome. To increase...

SIMOOOOOOOOOOON! You're resuming your wild bludgin' days? This thread was dead like 7 months 4 days ago! I have PLA already, mind you. Go to the chain thread instead!

You jump out of thin air again! Continue the thread. Repost the question: Assess the impacts on the environment of the developments in technology available to manufacture NaOH.

What? OK, define 'neutralization'.

danz, wake up! When you have 0.1 M acetic acid, and 0.001 M HCl, which one needs larger volume of NaOH 0.1 M to neutralize? (taking same volume for both acids) Acetic acid. Using a simple calculation when we have 1L of each acid. n CH3COOH = 0.1 * 1 = 0.1 n HCL = 0.001 *1 = 0.001...

So sorry that I hadnot seen this question until a few mins ago while surfin through the last few pages. Supposing we have the same volume for both of them, obviously for acetic acid to have pH 3, it should be of much higher concentration than HCl due to its weaker ionization energy. While...