for your question namu:
il try and make it as clear as possible but yaeh not so good with typing
using cartesian equation:
let y = 0 x = R+r
0 = h + (r+R)tan@ - g(r+R)^2/2v^2 cos@
you use v^2 from part c then there for
0> h+ (r+R)tan@ -((r+R)^2 tan @ )/R
then after this you...
ok well, you know that at a point a which is a<1 a has the same value y value of another point, an equal length from the axis of the parabola but in the other direction. so the distance from a to the axis of the parabola is 1-a and therefore the point 1-a away from x= 1 is 1+ 1-a = 2-a...