for this question i basically just made sample graphs lol
for y=x^2, if take the inverse u get y=sqrt x (assuming u take the positive), diffing it gives u 1/(2sqrt x), subbing x=1 gives a gradient of 1/2.
now if u diff y=x^2, u get y=2x, subbing in x=1 u get y=2.
Gradient of 2 and 1/2 is not...